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jQuery 调用 Ajax 实现查询的局部更新 (jsp + servlet + jQuery + Ajax)
阅读量:393 次
发布时间:2019-03-05

本文共 1821 字,大约阅读时间需要 6 分钟。

jQuery?Java Servlet??AJAX???????

???????????jQuery??Java Servlet?????????????????????????

??????

???????????HTML????????????

  • ??????????????
  • ????????AJAX??
  • ??????????????????

???????

????????

??????Java Servlet??????????

  • ???????????
  • ????????????
  • ?????????
  • ???????

    package com.syrdbt.system.servlet;
    import javax.servlet.ServletException;
    import javax.servlet.annotation.WebServlet;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    import java.io.IOException;
    @WebServlet("/TestAjaxServlet")
    public class TestAjaxServlet extends HttpServlet {
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
    request.setCharacterEncoding("utf-8");
    String name = request.getParameter("info");
    System.out.println("?????? " + name);
    if(name.equals("abc")) {
    response.getWriter().print("success");
    } else {
    response.getWriter().print("failed");
    }
    }
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
    doGet(request, response);
    }
    }

    ??????

  • HTML????

    • ????jQuery?
    • ?????????ID???JavaScript??
  • JavaScript????

    $(function() {
    $("#search").click(function() {
    var value = $("#info").val();
    $.ajax({
    type: 'POST',
    url: "TestAjaxServlet",
    data: "info=" + value,
    success: function(result) {
    $("#show").html(result);
    }
    });
    });
    });
  • ????????

    • ???????
    • ????????
    • ????
  • ?????

    ?????????????

  • ???????
  • ??????AJAX??
  • ???????????
  • ??????????
  • ??????????????????????????????HTML???????????????

    转载地址:http://fpkzz.baihongyu.com/

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